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A sum of money was divided between Tarun, Raghav and Kapil in the ratio 7 ∶ 4 ∶ 9. But, Kapil gave 1/3 of his share each to Tarun and Raghav. If Tarun received Rs. 1800 more than Raghav, then what is the total sum of money?

ARs. 6000

BRs. 9000

CRs. 12000

DRs. 15000

Answer:

C. Rs. 12000

Read Explanation:

Let Tarun, Raghav and Kapil initially received Rs. ‘7x’, Rs. ‘4x’ and Rs. ‘9x’ respectively Tarun’s final share = 7x + 9x/3 = 7x + 3x = 10x Raghav’s final share = 4x + 9x/3 = 4x + 3x = 7x Kapil’s final share = 9x/3 = 3x Tarun received Rs. 1800 more than Raghav, ⇒ 10x – 7x = 1800 ⇒ 3x = 1800 ⇒ x = 1800/3 = Rs. 600 Total sum of money = 7x + 4x + 9x = 20x = 20x(600) = Rs. 12000


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