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A thief saw a policeman and he started running at a speed of 12 m/s. After a certain time, the policeman starts running behind the thief at a speed of 18 m/s. If the policeman covered a 540 m distance to catch the thief, the time (in seconds) after which the policeman started running is:

A10

B12

C15

D18

Answer:

C. 15

Read Explanation:

Let’s correct it carefully.

Given:

  • Thief speed = 12 m/s

  • Policeman speed = 18 m/s

  • Distance covered by policeman till catch = 540 m

  • Need: time thief got head start

    Time taken by policeman to cover 540 m

t=54018=30 secondst = \frac{540}{18} = 30 \text{ seconds}

So policeman runs for 30 seconds.

Relative speed

18−12=6 m/s18 - 12 = 6 \text{ m/s}

Distance thief gains in 30 seconds

6×30=180 m6 \times 30 = 180 \text{ m}

Time thief had head start

Time=18012=15 seconds\text{Time} = \frac{180}{12} = 15 \text{ seconds}


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