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A train travelling at a speed of 60 km/h leaves station A at 7:00 a.m. and another train travelling at a speed of 84 km/h starts from station A at 9:30 a.m. in the same direction on a parallel track. At what distance (in km) from station A and after how many hours of travel of the second train will they be together? Express your answer in the same order.

A693 km, 8.25 hours

B525 km, 6.25 hours

C375 km, 6.25 hours

D495 km, 8.25 hours

Answer:

B. 525 km, 6.25 hours

Read Explanation:

Given:

  • Speed of first train = 60 km/h

  • Speed of second train = 84 km/h

  • First train starts at 7:00 a.m.

  • Second train starts at 9:30 a.m.

    Head start of the first train

Time gap = 2.5 hours

Distance covered by first train in 2.5 hours:
60×2.5=150 km60 \times 2.5 = 150 \text{ km}

Relative speed

8460=24 km/h84 - 60 = 24 \text{ km/h}

Time taken by second train to catch up

Time=15024=6.25 hours\text{Time} = \frac{150}{24} = 6.25 \text{ hours}

So, after 6.25 hours (6 hours 15 minutes) of travel of the second train, they meet.

Distance from station A

84×6.25=525 km84 \times 6.25 = 525 \text{ km}

=525 km, 6.25 hours


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