ABC is an equilateral triangle. Coordinates of A are (3, 0) and those of B are (7,0). The coordinates of C are:
A(2,2√3)
B(2√3, 2)
C(5,2√3)
D(2√3, 5)
A(2,2√3)
B(2√3, 2)
C(5,2√3)
D(2√3, 5)
Related Questions:
In a circle of centre O, PR = 3a + 5 and RQ = 5a – 5, OR = 15 units, ∠ORP = 90°. Find the radius of the circle.