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An individual invested certain amounts in three different schemes P, Q, and R at simple interest rates of 7% p.a., 9% p.a., and 11% p.a. respectively. If the total interest accrued in one year was ₹2520 and the amount invested in Scheme R was 250% of the amount invested in Scheme P and 300% of the amount invested in Scheme 0, what was the amount invested in Scheme P?

A₹5000

B₹5500

C₹6000

D₹6500

Answer:

C. ₹6000

Read Explanation:

Let the amount invested in Scheme P = ₹x.

Given:

  • P earns 7%

  • Q earns 9%

  • R earns 11%

  • Total interest in 1 year = ₹2520

  • R = 250% of P

  • R = 300% of Q (assuming “Scheme 0” means Scheme Q)

Step 1: Express Q and R in terms of x

R=250% of P=250100x=2.5xR=250\%\text{ of }P=\frac{250}{100}x=2.5x

Since (R=300%) of Q:

Q=R3=2.5x3=5x6Q=\frac{R}{3}=\frac{2.5x}{3}=\frac{5x}{6}

Step 2: Calculate the total interest

7%×x+9%×5x6+11%×2.5x=25207\%\times x+9\%\times\frac{5x}{6}+11\%\times2.5x=2520

0.07x+0.075x+0.275x=2520

0.42x=2520

x=25200.42=6000x=\frac{2520}{0.42}=6000

Answer: ₹6,000

So, the amount invested in Scheme P was ₹6,000.


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