To find the time it takes for the object to reach the ground, we can use the equation:
h = ut + (1/2)gt^2
where:
h = height (20 m)
u = initial velocity (0 m/s, since it's dropped from rest)
g = acceleration due to gravity (10 m/s^2)
t = time
Rearranging the equation to solve for t:
t = √(2h/g)
Plugging in the values:
t = √(2 x 20 m / 10 m/s^2)
= √(4 s^2)
= 2 s
The final answer is: 2 seconds