Question

Assume a spring extend by “d” due to some load. Let “F” be the spring force and “k’ the spring constant. Then, the potential energy stored is .....

• A. $2d/F^2$
• B. $F^2/2k$
• C. $2k/T^2$
• D. $$F^2/2d$$

Answer 1

Answer:

$F^2/2k$

F = k*d PE = 1/2*k*d2 = 1/2*F*d = 1/2*F*F/k = F2/2k.