Question

Based on the English alphabetical order, three of the following four letter-clusters are alike in a certain way and thus form a group. Which letter-cluster DOES NOT belong to that group? (Note: The odd man out is not based on the number of consonants/vowels or their position in the letter-cluster)

• A. NYJ
• B. TEP
• C. CNY
• D. QZK

Answer 1

Answer:

D. QZK

Alphabet positions

A = 1, B = 2, … Z = 26

NYJ

N(14) → Y(25) = +11
Y(25) → J(10) = −15

TEP

T(20) → E(5) = −15
E(5) → P(16) = +11

CNY

C(3) → N(14) = +11
N(14) → Y(25) = +11

---

QZK

Q(17) → Z(26) = +9 ❌
Z(26) → K(11) = −15

---

In NYJ, TEP, and CNY, the difference of +11 appears between at least one pair of consecutive letters.

❌ QZK does not follow this rule (it has +9 instead of +11).

---

QZK