Centre of gravity of a trapezium of height h and parallel sides a and b, measured from the side b is at a distance of
Ah(b+2a)/(2(b +a))
Bh(b+2a)/(2(b+a))
Ch(b+2a)/(3(b+a))
Dh(b+2a)/(3(b+a))
Ah(b+2a)/(2(b +a))
Bh(b+2a)/(2(b+a))
Ch(b+2a)/(3(b+a))
Dh(b+2a)/(3(b+a))
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