Question

$$Change the following recurring decimal into a fraction.

$0.\overline{49}$

• A. 49/100
• B. 49/90
• C. 49/99
• D. 49/9

Answer 1

Answer:

C. 49/99

$let,{x}=0.49\overline{49}$

$100x=49.49\overline{49}$

$99x=100x-x$

$99x=49$

$\implies{x}=\frac{49}{99}$

$OR$

$\overline{abcd}=\frac{repeated term}{number of 9s for the repeated term}$

$0.\overline{49}=\frac{49}{99}$