Consider the redox reaction
Which species acts as the oxidising agent in this reaction ?
ACr2O7^2-
BS02
CCr3+
DSO4^2-
Answer:
A. Cr2O7^2-
Read Explanation:
Redox reactions involve the transfer of electrons between chemical species. Oxidation is the loss of electrons, while reduction is the gain of electrons. An oxidising agent is a substance that accepts electrons from another substance, causing that other substance to be oxidised, and is itself reduced in the process.
Analysing the Given Reaction
The reaction involves:
Dichromate ion (Cr2O72-)
Sulphite ion (SO32-)
Acidic medium (H+)
Chromium(III) ions (Cr3+)
Sulphate ions (SO42-)
Water (H2O)
Determining Oxidation States
To identify the oxidising agent, we need to determine the changes in oxidation states of the elements involved:
In Cr2O72-: Oxygen usually has an oxidation state of -2. Let the oxidation state of Chromium be 'x'. So, 2x + 7(-2) = -2. This gives 2x - 14 = -2, so 2x = +12, and x = +6.
In SO32-: Oxygen has an oxidation state of -2. Let the oxidation state of Sulfur be 'y'. So, y + 3(-2) = -2. This gives y - 6 = -2, so y = +4.
In Cr3+: The oxidation state of Chromium is directly given as +3.
In SO42-: Oxygen has an oxidation state of -2. Let the oxidation state of Sulfur be 'z'. So, z + 4(-2) = -2. This gives z - 8 = -2, so z = +6.
Identifying Oxidation and Reduction
Chromium (Cr): Its oxidation state changes from +6 in Cr2O72- to +3 in Cr3+. This decrease in oxidation state signifies reduction (gain of electrons).
Sulfur (S): Its oxidation state changes from +4 in SO32- to +6 in SO42-. This increase in oxidation state signifies oxidation (loss of electrons).
