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Consider the redox reaction

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Which species acts as the oxidising agent in this reaction ?

ACr2O7^2-

BS02

CCr3+

DSO4^2-

Answer:

A. Cr2O7^2-

Read Explanation:

  • Redox reactions involve the transfer of electrons between chemical species. Oxidation is the loss of electrons, while reduction is the gain of electrons. An oxidising agent is a substance that accepts electrons from another substance, causing that other substance to be oxidised, and is itself reduced in the process.

Analysing the Given Reaction

The reaction involves:

  • Dichromate ion (Cr2O72-)

  • Sulphite ion (SO32-)

  • Acidic medium (H+)

  • Chromium(III) ions (Cr3+)

  • Sulphate ions (SO42-)

  • Water (H2O)

Determining Oxidation States

To identify the oxidising agent, we need to determine the changes in oxidation states of the elements involved:

  • In Cr2O72-: Oxygen usually has an oxidation state of -2. Let the oxidation state of Chromium be 'x'. So, 2x + 7(-2) = -2. This gives 2x - 14 = -2, so 2x = +12, and x = +6.

  • In SO32-: Oxygen has an oxidation state of -2. Let the oxidation state of Sulfur be 'y'. So, y + 3(-2) = -2. This gives y - 6 = -2, so y = +4.

  • In Cr3+: The oxidation state of Chromium is directly given as +3.

  • In SO42-: Oxygen has an oxidation state of -2. Let the oxidation state of Sulfur be 'z'. So, z + 4(-2) = -2. This gives z - 8 = -2, so z = +6.

Identifying Oxidation and Reduction

  • Chromium (Cr): Its oxidation state changes from +6 in Cr2O72- to +3 in Cr3+. This decrease in oxidation state signifies reduction (gain of electrons).

  • Sulfur (S): Its oxidation state changes from +4 in SO32- to +6 in SO42-. This increase in oxidation state signifies oxidation (loss of electrons).


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