A5
B2
C3
D4
Answer:
Related Questions:
If x = 2⁸ and xx=2yx^x = 2^yxx=2y, then find the value of 'y'.
23×43×(65)2(36)4×(16)3= \frac {2^3 \times 4^3 \times (6^5)^2} {(36)^4 \times (16)^3} =(36)4×(16)323×43×(65)2=
Simplify (32)3+(22)2(3^2)^3+ (2^2)^2(32)3+(22)2
10240.2=?1024^{0.2}=?10240.2=?
