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Each of P, Q, R, S, T, U and V has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. R has an exam on Wednesday. Exactly 3 people have an exam between R and U. V has an exam immediately after S and Q has an exam immediately before S. Only 3 people have an exam between P and S. Who has an exam on Monday?

AQ

BP

CV

DU

Answer:

B. P

Read Explanation:

  • Correct Answer : Option B (P).

  • Let the exam days be Monday → Sunday. We know:

    • R is on Wednesday.

    • V is immediately after S.

    • Q is immediately before S ⟹ the order is Q – S – V consecutively.

    • Exactly 3 people have an exam between R and U
      ⇒ between R (Wednesday) and U there are 3 exams, so the day-gap is 4.

      • If R is Wed, then U must be Sunday (Wed → Thu(1) → Fri(2) → Sat(3) → Sun(4)).
        ⟹ U = Sunday.

    • Since U is Sunday, the pair S – V must be somewhere before Sunday, because V is after S.

  • Now look at Q – S – V as consecutive days. Also:

    • Only 3 people have an exam between P and S
      ⇒ between P and S there are 3 exams, so P is 4 days away from S.

    • And there are 7 total persons: P, Q, R, S, T, U, V with all different days.

  • We already have:

    • R = Wednesday

    • U = Sunday

  • Try placing the consecutive block Q – S – V:

    • If S = Friday, then Q = Thursday and V = Saturday.
      Then we test the condition for P and S:

      • “3 people between P and S” means P is 4 days away from S.

      • If S = Friday, then P must be Monday (Mon → Tue(1) → Wed(2) → Thu(3) → Fri(4)).
        This satisfies the spacing condition.

  • So the full mapping includes:

    • Q = Thursday

    • S = Friday

    • V = Saturday

    • R = Wednesday

    • U = Sunday

    • Remaining day is Tuesday for T

    • And P = Monday

  • Therefore, the person having the exam on Monday is P.

  • Correct Answer : Option B (P)

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