Question

Each of P, Q, R, S, T, U and V has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. R has an exam on Wednesday. Exactly 3 people have an exam between R and U. V has an exam immediately after S and Q has an exam immediately before S. Only 3 people have an exam between P and S. Who has an exam on Monday?

• A. Q
• B. P
• C. V
• D. U

Answer 1

Answer:

B. P

• Correct Answer : Option B (P).

• Let the exam days be Monday → Sunday. We know:

  • R is on Wednesday.

  • V is immediately after S.

  • Q is immediately before S ⟹ the order is Q – S – V consecutively.

  • Exactly 3 people have an exam between R and U
    ⇒ between R (Wednesday) and U there are 3 exams, so the day-gap is 4.

    • If R is Wed, then U must be Sunday (Wed → Thu(1) → Fri(2) → Sat(3) → Sun(4)).
      ⟹ U = Sunday.

  • Since U is Sunday, the pair S – V must be somewhere before Sunday, because V is after S.

• Now look at Q – S – V as consecutive days. Also:

  • Only 3 people have an exam between P and S
    ⇒ between P and S there are 3 exams, so P is 4 days away from S.

  • And there are 7 total persons: P, Q, R, S, T, U, V with all different days.

• We already have:

  • R = Wednesday

  • U = Sunday

• Try placing the consecutive block Q – S – V:

  • If S = Friday, then Q = Thursday and V = Saturday.
    Then we test the condition for P and S:

    • “3 people between P and S” means P is 4 days away from S.

    • If S = Friday, then P must be Monday (Mon → Tue(1) → Wed(2) → Thu(3) → Fri(4)).
      This satisfies the spacing condition.

• So the full mapping includes:

  • Q = Thursday

  • S = Friday

  • V = Saturday

  • R = Wednesday

  • U = Sunday

  • Remaining day is Tuesday for T

  • And P = Monday

• Therefore, the person having the exam on Monday is P.

• Correct Answer : Option B (P)