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Equation of the line passing through the points (1,-1) and (3,5) :

A4x-y+5 =0

B4x+y+5 =0

C3x-y-4=0

D2x-y-5 =0

Answer:

C. 3x-y-4=0

Read Explanation:

Eqn of the line by

yy1xx1=y2y1x2x1\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}

y+1x1=5+131\frac{y+1}{x-1}=\frac{5+1}{3-1}

y+1x1=62\frac{y+1}{x-1}=\frac{6}{2}

(y+1)=3(x1)(y+1)=3(x-1)

3x3=(y+1)3x-3=(y+1)

3xy4=03x-y-4=0


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