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Evaluate: 41 - [21 - {11 - (15 - 6 ÷ 3 × 3)}]

A17

B24

C19

D22

Answer:

D. 22

Read Explanation:

The final value of the expression is $22$.

1. Solve Innermost Parentheses

First, evaluate the operations inside the round parentheses $(15 - 6 \div 3 \times 3)$ by following the BODMAS/PEMDAS rule (division and multiplication from left to right, then subtraction):

  • Divide numbers: $6 \div 3 = 2$

  • Multiply numbers: $2 \times 3 = 6$

  • Subtract numbers: $15 - 6 = 9$

The expression now becomes:
$41 - [21 - \{11 - 9\}]$

2. Solve Curly Braces

Next, calculate the terms inside the curly braces $\{11 - 9\}$:

  • Subtract numbers: $11 - 9 = 2$

The expression simplifies to:
$41 - [21 - 2]$

3. Solve Square Brackets

Now, evaluate the subtraction inside the square brackets $[21 - 2]$:

  • Subtract numbers: $21 - 2 = 19$

This reduces the expression to:
$41 - 19$

4. Final Subtraction

Perform the final subtraction to get the result:

  • Subtract numbers: $41 - 19 = 22$

Final Answer

The final evaluated value of the expression $41 - [21 - {11 - (15 - 6 \div 3 \times 3)}]$ is $22$.


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5(21 - 7) + 7 × 2 =

2+10×10÷10×10= 2 + 10 \times10 \div 10 \times 10 =

'+' ഗുണനത്തേയും '-' ഹരണത്തെയും 'x' സങ്കലത്തെയും '/' വ്യവകലനത്തെയും സൂചിപ്പിക്കുന്നുവെങ്കിൽ ( (35 x 20) + (25 / 15) ) - 5 എത്ര ?
കണ്ടുപിടിക്കുക : 10÷2×5+5=
18 ÷ (2x18 ÷ 6-5) എത്ര ?