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Evaluate: 41 - [21 - {11 - (15 - 6 ÷ 3 × 3)}]

A17

B24

C19

D22

Answer:

D. 22

Read Explanation:

The final value of the expression is $22$.

1. Solve Innermost Parentheses

First, evaluate the operations inside the round parentheses $(15 - 6 \div 3 \times 3)$ by following the BODMAS/PEMDAS rule (division and multiplication from left to right, then subtraction):

  • Divide numbers: $6 \div 3 = 2$

  • Multiply numbers: $2 \times 3 = 6$

  • Subtract numbers: $15 - 6 = 9$

The expression now becomes:
$41 - [21 - \{11 - 9\}]$

2. Solve Curly Braces

Next, calculate the terms inside the curly braces $\{11 - 9\}$:

  • Subtract numbers: $11 - 9 = 2$

The expression simplifies to:
$41 - [21 - 2]$

3. Solve Square Brackets

Now, evaluate the subtraction inside the square brackets $[21 - 2]$:

  • Subtract numbers: $21 - 2 = 19$

This reduces the expression to:
$41 - 19$

4. Final Subtraction

Perform the final subtraction to get the result:

  • Subtract numbers: $41 - 19 = 22$

Final Answer

The final evaluated value of the expression $41 - [21 - {11 - (15 - 6 \div 3 \times 3)}]$ is $22$.


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Simplify  234×[8−(6+2)×3]+4234\,\,234 \times [8 - (6 + 2) \times 3] + 4234

Find the value of

[(63÷9)×[147+191×(7−6)]][(63 \div 9) \times [\frac{14}{7}+\frac{19}{1}\times(7-6)]]