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Evaluate: 41 - [36 - {48 ÷ 2 - (6 - 12 ÷ 2) ÷ 2}]

A29

B30

C31

D28

Answer:

A. 29

Read Explanation:

The value of the expression is 29.

  1. Solve the innermost parentheses ( ):

    • First, do the division inside: 12÷2=612 \div 2 = 6

    • Then subtract: 66=06 - 6 = \mathbf{0}

  2. Solve the curly braces { }:

    • The expression becomes: {48÷20÷2}\{48 \div 2 - 0 \div 2\}

    • Solve the divisions: 48÷2=2448 \div 2 = 24 and 0÷2=00 \div 2 = 0

    • Subtract: 240=2424 - 0 = \mathbf{24}

  3. Solve the square brackets [ ]:

    • The expression becomes: [3624]=12[36 - 24] = \mathbf{12}

  4. Final Subtraction:

    • 4112=2941 - 12 = \mathbf{29}


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