Question

Evaluate:
$6-[\frac{2}{3}\div [\frac{1}{6}+(\frac{1}{2}\times(1-\frac{1}{3})]]$

• A. 14/3
• B. 15/3
• C. 16/3
• D. 17/3

Answer 1

Answer:

A. 14/3

Evaluate step by step:

$6-\left[\frac{2}{3}\div \left[\frac{1}{6}+\left(\frac{1}{2}\times\left(1-\frac{1}{3}\right)\right)\right]\right]$

First solve inside parentheses:

$1-\frac{1}{3}=\frac{2}{3}$

$\frac{1}{2}\times\frac{2}{3}=\frac{1}{3}$
]

Now:

$\frac{1}{6}+\frac{1}{3}$

$=\frac{1}{6}+\frac{2}{6}=\frac{3}{6}=\frac{1}{2}$

Now:

$\frac{2}{3}\div\frac{1}{2}$

$=\frac{2}{3}\times 2=\frac{4}{3}$

Finally:

$6-\frac{4}{3}$

$=\frac{18}{3}-\frac{4}{3}=\frac{14}{3}$

So the answer is:

$\boxed{\frac{14}{3}}$