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|f a $ b = 2, where a $ b = a² - b, what is the value of a and b?

A2,2

B8,1

C4,5

D9,6

Answer:

A. 2,2

Read Explanation:

Given:

a b= b = a^2 - b<br></p><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;">and</p><pdata−pxy="true"style="color:rgb(0,0,0);margin−top:2px;margin−bottom:2px;"><br>a<br></p><p data-pxy="true" style="color: rgb(0,0,0); margin-top: 2px; margin-bottom: 2px;">and</p><p data-pxy="true" style="color: rgb(0,0,0); margin-top: 2px; margin-bottom: 2px;"><br>a b = 2

Substituting the definition:

a2−b=2a^2 - b = 2

So,

b=a2−2b = a^2 - 2

This equation alone does not uniquely determine (a) and (b). There are infinitely many pairs satisfying it.

Examples:

  • (a = 2,; b = 2)

Therefore, (a) and (b) cannot be uniquely found unless an additional condition is given. The relation between them is:

b=a2−2\boxed{b = a^2 - 2}


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