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f5 * 4 = 41 and 6 * 3 = 45, what is 7 * 2?

A48

B51

C53

D55

Answer:

C. 53

Read Explanation:

A simple rule that fits both examples is:

a∗b=(a×b)+21a * b = (a \times b) + 21

Check:

  • (5∗4=(5×4)+21=20+21=41)(5 * 4 = (5 \times 4) + 21 = 20 + 21 = 41)

  • (6∗3=(6×3)+21=18+21=39),which<b>doesnot</b>equal45(6 * 3 = (6 \times 3) + 21 = 18 + 21 = 39), which <b>does not</b> equal 45

So that rule doesn't work.

Another rule:

a∗b=a2+b2a * b = a^2 + b^2

  • (5∗4=25+16=41)(5 * 4 = 25 + 16 = 41)

  • (6∗3=36+9=45)(6 * 3 = 36 + 9 = 45)

Therefore,

7∗2=49+4=537 * 2 = 49 + 4 = \boxed{53}

Answer:(53)Answer: (\boxed{53})


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