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Find Rate of interest for the sum of 10000 for 2years componded annually amounts to Rs.40000?

A200 %

B100 %

C400 %

D50 %

Answer:

B. 100 %

Read Explanation:

$$ In Compound interest

$Amount=P(1+\frac{r}{100})^2$

$40000=10000(1+\frac{r}{100})^2$

$(1+\frac{r}{100})^2=\frac{40000}{10000}$

$(1+\frac{r}{100})^2=\frac{4}{1}$

$1+\frac{r}{100}=2$

$\frac{r}{100}=2-1$

$r=100$


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