Question

Find the average of $1^2+2^2+3^2+.....+10^2$

• A. 385
• B. 231/6
• C. 55
• D. 231

Answer 1

Answer:

B. 231/6

Sum = n(n+1)(2n+1)/6

Average = (n+1)(2n+1)/6

$=(10+1)(20+1)/6$

$=231/6$