Find the distance between top and bottom side of the parallelogram ABCD with side AC = 8, angle BAC = 60°

Challenger App

Home
Questions
Quiz
Notes
Blog
Contact Us
e-Book

No.1 PSC Learning App

★

1M+ Downloads

Get App

Find the distance between top and bottom side of the parallelogram ABCD with side AC = 8, angle BAC = 60°

B4√3

C8√2

D16√3

Answer:

B. 4√3

Read Explanation:

distance = b × sinx

b = 8 x = 60

distance = 8 × sin 60

= 8 × √3/2

= 4√3

Read more in App

Related Questions:

Find the value of sin²35° + sin²55°

A shadow of a tower standing on a level ground is found to be 40√3 meters longer when the Sun's altitude is 30° than when it is 60°. The height of the tower is:

Find the area of a parallelogram with sides B = 6, AC = 3, and ∠ BAC = 60.

P and Q are the mid points of AB and AC respectively. R is a point on BC. Area of triangle PBR is 12 square centimeters and that of triangle QRC is 18 square centimeters what is the area of triangle PQR ?