Find the nature of roots of the quadratic equation: $x^2+16x+64=0$

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Find the nature of roots of the quadratic equation:

$x^2+16x+64=0$

Areal, unequal, and irrational

Bcomplex without real parts

Creal, equal, and irrational

Dreal equal and rational

Answer:

$x^2+16x+64=0$

$a=1,b=16,c=74$

$b^2-4ac=16^2-4\times1\times64$

$=256-256$

$=0$

$b^2-4ac=0$

The roots are real equal and rational

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