Question

Find the nature of roots of the quadratic equation:

$x^2+16x+64=0$

• A. real, unequal, and irrational
• B. complex without real parts
• C. real, equal, and irrational
• D. real equal and rational

Answer 1

Answer:

D. real equal and rational

$x^2+16x+64=0$

$a=1,b=16,c=74$

$b^2-4ac=16^2-4\times1\times64$

$=256-256$

$=0$

$b^2-4ac=0$

The roots are real equal and rational