Find the nature of the roots of x² - 14x + 49 = 0ADistinct rootsBReal and equal rootsCImaginary rootsDNo real rootsAnswer: B. Real and equal roots Read Explanation: b2−4ac=(−14)2−4×1×49b^2-4ac=(-14)^2-4\times 1\times 49b2−4ac=(−14)2−4×1×49=196−196=0=196-196=0=196−196=0Real and equal roots Read more in App
