Question

Find the nature of the roots of x² - 14x + 49 = 0

• A. Distinct roots
• B. Real and equal roots
• C. Imaginary roots
• D. No real roots

Answer 1

Answer:

B. Real and equal roots

$b^2-4ac=(-14)^2-4\times 1\times 49$

$=196-196=0$

Real and equal roots