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Find the number of 2-digit numbers divisible by both 2 and 4.

A12

B22

C42

D32

Answer:

B. 22

Read Explanation:

Step 1 Identify the smallest 2-digit number divisible by 4: 12. Step 2 Identify the largest 2-digit number divisible by 4: 96. Step 3 Use the formula for the number of terms in an arithmetic sequence: n = (l - a) / d + 1. Step 4 Substitute the values: n = (96 - 12) / 4 + 1. Step 5 Calculate: n = 84 / 4 + 1 = 21 + 1 = 22. Final Answer: 22


Related Questions:

If a number is in the form of 810×97×788^{10} \times9^7\times7^8, find the total number of prime factors of the given number.

2 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 1 ഉം 3 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 2 ഉം 4 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 3 ഉം 5 കൊണ്ടു ഹരിച്ചാൽ ശിഷ്ടം 4 ഉം കിട്ടുന്ന ഏറ്റവും ചെറിയ സംഖ്യ ഏത്
Find the smallest square number from among the given options, which is divisible by each of 8, 15 and 20.

When a natural number n is divided by 5 the remainder is 4. What is the remainder when 2n is divided by 5?

A. 2

B. 3

C. 4

D. 0

How many two-digit numbers are divisible by 5?