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Find the number of zeros at the right end of 100!

A20

B30

C24

D15

Answer:

C. 24

Read Explanation:

Highest power of 2 in 100! is 97 And highest power of 5 in 100! is 24 Each pair of 2 and 5 will give rise to a 10 or a zero at the end. Hence the number of zeroes at the end in 100! is equal to 24. OR number of zeros at the right end of 100 = power of 5 in 100! divide 100 by 5 No. of zeroes = Sum of all quotient. Divide divisor by 5 and add the respective quotient. 100 ÷ 5 = 20. 20 ÷ 5 = 4. Adding the respective quotients. 20 + 4 = 24


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