Find the number of zeros at the right end of 100!
A20
B30
C24
D15
Answer:
C. 24
Read Explanation:
Highest power of 2 in 100! is 97 And highest power of 5 in 100! is 24 Each pair of 2 and 5 will give rise to a 10 or a zero at the end. Hence the number of zeroes at the end in 100! is equal to 24. OR number of zeros at the right end of 100 = power of 5 in 100! divide 100 by 5 No. of zeroes = Sum of all quotient. Divide divisor by 5 and add the respective quotient. 100 ÷ 5 = 20. 20 ÷ 5 = 4. Adding the respective quotients. 20 + 4 = 24