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Find the perimeter of a sector with central angle 90 and radius 14cm

A44cm

B50cm

C74cm

D28cm

Answer:

B. 50cm

Read Explanation:

Perimeter of a sector=2πr×θ/360+2r= 2\pi{r}\times\theta/360+ 2r

=2π×14×90/360+2×14=2\pi\times14\times90/360+2\times14

=2×22/7×14×1/4+28=2\times22/7\times14\times1/4+28

=22+28=22+28

=50=50


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