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Find the quadratic equation that has (1 + √3) as one of its roots.

Ax²+2x+1=0

Bx²+2x+2=0

Cx²-2x-2=0

Dx² + √3x + 1 = 0

Answer:

C. x²-2x-2=0

Read Explanation:

x²-2x-2=0


Related Questions:

The equation x²-6x+9=0 can be written as:
image.png
Find the degree of the polynomial with P(1) = -1 and P(-2) = 3.

The equation(x2)2+1=2x3(x-2)^2+1=2x-3is:

image.png