Find the quadratic equation that has (1 + √3) as one of its roots.

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Ax²+2x+1=0

Bx²+2x+2=0

Cx²-2x-2=0

Dx² + √3x + 1 = 0

Answer:

x²-2x-2=0

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If $1 + \sqrt{3}$ and $1 - \sqrt{3}$ are the roots of a quadratic equation, then the quadratic equation is: