Find the second degree polynomial with P(0)=0, P(1)=1 and P(2)=6
A3x² + -1x = 0
B2x² + 2x + 1 = 0
C2x² + -1x = 0
Dx² + 2x + 1 = 0
Answer:
C. 2x² + -1x = 0
Read Explanation:
P(x)= ax² + bx + c
P(0) = c =0 ...... (1)
P(1) = a + b + c =1 .........(2)
P(2) = a × 2² + b × 2 + c = 6
4a + 2b + c =6
4a + 2b = 6
2a + b = 3 ..........(3)
from (2) and (3)
a = 2
b = -1
So ,
P(x) = 2x² + -1x = 0
