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Find the second degree polynomial with P(0)=0, P(1)=1 and P(2)=6

A3x² + -1x = 0

B2x² + 2x + 1 = 0

C2x² + -1x = 0

Dx² + 2x + 1 = 0

Answer:

C. 2x² + -1x = 0

Read Explanation:

P(x)= ax² + bx + c P(0) = c =0 ...... (1) P(1) = a + b + c =1 .........(2) P(2) = a × 2² + b × 2 + c = 6 4a + 2b + c =6 4a + 2b = 6 2a + b = 3 ..........(3) from (2) and (3) a = 2 b = -1 So , P(x) = 2x² + -1x = 0


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