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Find the simple interest (in ₹) on ₹3000 as a sum borrowed at 9% per year rate of interest for 3 years.

A770

B850

C750

D810

Answer:

D. 810

Read Explanation:

Use the simple interest formula:
SI=P×R×T100SI = \frac{P \times R \times T}{100}

Substitute:
SI=3000×9×3100SI = \frac{3000 \times 9 \times 3}{100}

SI=81000100=810SI = \frac{81000}{100} = 810

Final Answer: ₹810


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