Challenger App

No.1 PSC Learning App

1M+ Downloads

Find the value of 4912\frac{\frac{4}{9}}{12}

A125\frac{1}{25}

B127\frac{1}{27}

C129\frac{1}{29}

D126\frac{1}{26}

Answer:

127\frac{1}{27}

Read Explanation:

Calculation:

4912=49×12\frac{\frac{4}{9}}{12}=\frac{4}{9\times{12}}

=127=\frac{1}{27}


Related Questions:

image.png
3/4 + 1/2 എത്രയാണ് ?

2510+535=?2\frac5{10}+5\frac35=?

Simplify: 1(523).\frac{1}{(5-2\sqrt{3})}.

6711+1315227333X=7131106\frac{7}{11}+13\frac{15}{22}-7\frac{3}{33}-X=7\frac{13}{110}

$$ആണെങ്കിൽ x എത്ര ?