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Find the value of
[(12÷4)×[155+161×(98)]][(12 \div 4)\times[\frac{15}{5}+ \frac{16}{1}\times(9-8)]]

A57

B44

C69

D61

Answer:

A. 57

Read Explanation:

Let’s simplify step by step:

[(12÷4)×[155+161×(98)]][(12 \div 4)\times[\frac{15}{5}+ \frac{16}{1}\times(9-8)]]
Solve brackets

12÷4=312 \div 4 = 3
98=19 - 8 = 1
Substitute values

3×[155+161×1]3 \times \left[\frac{15}{5} + \frac{16}{1} \times 1 \right]
Simplify fractions

155=3,161=16\frac{15}{5} = 3,\quad \frac{16}{1} = 16
So expression becomes:
3×(3+16×1)3 \times (3 + 16 \times 1)
Multiply first

16×1=1616 \times 1 = 16
3+16=193 + 16 = 19
Final multiplication

3×19=573 \times 19 = 57
Final Answer:

57\boxed{57}


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