Challenger App

No.1 PSC Learning App

1M+ Downloads

Find the value of [(14÷2)×[147+403×(74)][(14 \div 2 ) \times [\frac{14}{7}+\frac{40}{3}\times(7-4)]

A310

B274

C277

D294

Answer:

D. 294

Read Explanation:

Let’s simplify step by step:

[(14÷2)×(147+403×(74))][(14 \div 2) \times \left(\frac{14}{7} + \frac{40}{3} \times (7 - 4)\right)]

  1. (14 \div 2 = 7)

  2. (7 - 4 = 3)

  3. (\frac{40}{3} \times 3 = 40)

  4. (\frac{14}{7} = 2)

So inside the bracket:
2+40=422 + 40 = 42

Now:
7×42=2947 \times 42 = 294

Answer: 294


Related Questions:

Which of the following options is the closest approximate value which will come in place of question mark (?) in the following equation: 2519 ÷ 3 +441 - 109 = ?
9 - [8 - (8 - 6 × 2) ÷ 4] =?

What are the two signs to be interchanged for making the following equation correct ?

$\left[ \left\{ (44 \mathbf{-} 36) \mathbf{+} (4 \times 4) \right\} \div (1 \mathbf{+} 5) \right] \times 2 = 8$

15 + 33 ÷ 11 × (12 ÷ 3) – 10 കണക്കാക്കുക
(3 + 8) × 4 - 2 × (4 + 7) =