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Find the value of

[(42÷7)×(423+194×(84))][(42\div7)\times(\frac{42}{3}+\frac{19}{4}\times(8-4))]

A180

B209

C198

D202

Answer:

C. 198

Read Explanation:

Evaluate step by step:

[(42÷7)×(423+194×(84))][(42 \div 7)\times(\frac{42}{3}+\frac{19}{4}\times(8-4))]

Simplify inside brackets

42÷7=642 \div 7 = 6
84=48 - 4 = 4
194×4=19\frac{19}{4} \times 4 = 19


423=14\frac{42}{3} = 14

Add inside parentheses

14+19=3314 + 19 = 33

Final multiplication

6×33=1986 \times 33 = 198

Final Answer:

198


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[(63÷9)×[147+191×(76)]][(63 \div 9) \times [\frac{14}{7}+\frac{19}{1}\times(7-6)]]

image.png

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