Find the value of $[(48 \div 8)\times[\frac{49}{7}+\frac{40}{4}\times(7-3)]] A282B286C284D273Answer: A. 282 Read Explanation: Let’s solve step by step:(48÷8)×[497+404×(7−3)]](48 \div 8)\times[\frac{49}{7}+\frac{40}{4}\times(7-3)]](48÷8)×[749+440×(7−3)]]48÷8=648 \div 8 = 648÷8=6497=7\frac{49}{7} = 7749=7404=10\frac{40}{4} = 10440=10(7−3)=4(7 - 3) = 4(7−3)=4So,10×4=4010 \times 4 = 4010×4=407+40=477 + 40 = 477+40=476×47=2826 \times 47 = \boxed{282}6×47=282Final Answer: 282 Read more in App