Find the value of [(84÷6)×[917+162×(8−6)]][(84 \div 6)\times[\frac{91}{7}+\frac{16}{2}\times (8-6)]][(84÷6)×[791+216×(8−6)]] A409B426C400D406Answer: D. 406 Read Explanation: Let’s simplify step by step:(84÷6)×[917+162×(8−6)]](84 \div 6)\times[\tfrac{91}{7}+\tfrac{16}{2}\times (8-6)]](84÷6)×[791+216×(8−6)]](84÷6=14)(84 \div 6 = 14)(84÷6=14)(917=13)(\tfrac{91}{7} = 13)(791=13)(8−6=2)(8 - 6 = 2)(8−6=2)(162=8)(\tfrac{16}{2} = 8)(216=8)(8×2=16)(8 \times 2 = 16)(8×2=16)13+16=2913 + 16 = 2913+16=2914×29=40614 \times 29 = 40614×29=406 Read more in App