Find the value of $[(84 \div 6)\times[\frac{91}{7}+\frac{16}{2}\times (8-6)]]$

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A409

B426

C400

D406

Answer:

Let’s simplify step by step:

$(84 \div 6)\times[\tfrac{91}{7}+\tfrac{16}{2}\times (8-6)]]$

$(84 \div 6 = 14)$

$(\tfrac{91}{7} = 13)$

$(8 - 6 = 2)$

$(\tfrac{16}{2} = 8)$

$(8 \times 2 = 16)$

$13 + 16 = 29$

$14 \times 29 = 406$

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