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Find the value of [(91÷7)×[644+176×(8−2)]][(91 \div 7)\times[\frac{64}{4}+\frac{17}{6}\times(8-2)]]

A434

B447

C432

D429

Answer:

D. 429

Read Explanation:

Evaluate step by step:

[(91÷7)×[644+176×(8−2)]]\left[\left(91 \div 7\right)\times\left[\frac{64}{4}+\frac{17}{6}\times(8-2)\right]\right]

First, solve inside the brackets:

91÷7=1391 \div 7 = 13
644=16\frac{64}{4} = 16
8−2=68 - 2 = 6
176×6=17\frac{17}{6} \times 6 = 17

Now:

16 + 17 = 33

Finally:

13×33=42913 \times 33 = 429

So, the value is:

429\boxed{429}


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