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Find the value of

[(30÷5)×{306+191×(4−3)}]\left[ (30 \div 5) \times \left\{ \frac{30}{6} + \frac{19}{1} \times (4 - 3) \right\} \right]

A144

B155

C132

D157

Answer:

A. 144

Read Explanation:

The final value of the expression is 144.

  1. Solve the innermost round brackets (⋅)( \cdot ):

    • 30÷5=630 \div 5 = 6

    • 4−3=14 - 3 = 1

    Substitute these back into the expression:
    [6×{306+191×1}]\left[ 6 \times \left\{ \frac{30}{6} + \frac{19}{1} \times 1 \right\} \right]

  2. Simplify the fractions and multiplication inside the curly braces {⋅}\{ \cdot \}:

    • Simplify fractions: 306=5\frac{30}{6} = 5 and 191=19\frac{19}{1} = 19

    • Perform multiplication first: 19×1=1919 \times 1 = 19

    • Perform addition next: 5+19=245 + 19 = 24

    Substitute this back into the expression:
    [6×24]\left[ 6 \times 24 \right]

  3. Solve the final square brackets [⋅][ \cdot ]:

    • 6×24=1446 \times 24 = 144


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