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Find the value of cot2θcos2θ\sqrt{cot^2\theta-cos^2\theta}.

Acot θ cosec θ

B1

Ccos θ cosec θ

Dcot θ cos θ

Answer:

D. cot θ cos θ

Read Explanation:

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In the figure, AB=4 centimetres, BC =5 centimetres. <B=90° cos C is:

P and Q are the mid points of AB and AC respectively. R is a point on BC. Area of triangle PBR is 12 square centimeters and that of triangle QRC is 18 square centimeters what is the area of triangle PQR ?

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