(45)3×(45)−6=(45)2x−1(\frac{4}{5})^3\times(\frac{4}{5})^{-6}=(\frac{4}{5})^{2x-1}(54)3×(54)−6=(54)2x−1 x ന്റെ മൂല്യം കണ്ടെത്തുക A2B-2C1D-1Answer: D. -1 Read Explanation: (45)3×(45)−6=(45)2x−1(\frac{4}{5})^3\times(\frac{4}{5})^{-6}=(\frac{4}{5})^{2x-1}(54)3×(54)−6=(54)2x−1 (45)3−6=(45)2x−1(\frac{4}{5})^{3-6}=(\frac45)^{2x-1}(54)3−6=(54)2x−1 (45)−3=(45)2x−1(\frac{4}{5})^-3=(\frac{4}{5})^{2x-1}(54)−3=(54)2x−1 2x−1=−32x-1=-32x−1=−3 2x=−22x=-22x=−2 x=−1x=-1x=−1 Read more in App
