x ന്റെ മൂല്യം കണ്ടെത്തുക, 3x+8=272x+13^{x+8}=27^{2x+1}3x+8=272x+1 A0B1C2D-1Answer: B. 1 Read Explanation: 3x+8=272x+13^{x+8}=27^{2x+1}3x+8=272x+13x+8=(33)2x+13^{x+8}=({3^3})^{2x+1}3x+8=(33)2x+13x+8=36x+33^{x+8} = 3^{{6x}+3}3x+8=36x+3ax=ay ⟹ x=ya^{x}=a^y\implies{x=y}ax=ay⟹x=yx+8=6x+3x + 8 = 6x + 3x+8=6x+35x=55x = 55x=5x=1x=1x=1 Read more in App