Find the zero of the polynomial : 3x+2=03x + 2=03x+2=0 A2/3B-2/3C-3/2D3/2Answer: B. -2/3 Read Explanation: Given:q(x)=3x+2q(x)=3x+2q(x)=3x+2To find the zero polynomial,q(x)=0q(x)=0q(x)=03x+2=03x + 2=03x+2=03x=−23x=-23x=−2x=−2/3x =-2/3x=−2/3 Read more in App