Question

Find two consecutive odd positive integers, sum of whose squares is 290?

• A. 9, 11
• B. 11,13
• C. 7, 9
• D. 13, 15

Answer 1

Answer:

B. 11,13

Let two consecutive odd positive integers be X, X + 2

$X^2 + (X+2)^2=290$

$X^2+X^2+4X+4= 290$

$2X^2+4X-286=0$

$X^2+2X-143=0$

$X=11$

$X+2=13$