Find x in the following:
6157+x=853
A$2\frac{2}{15}$
B$2\frac{3}{15}$
C$6\frac{3}{5}$
D$5\frac{4}{5}$
Answer:
$2\frac{2}{15}$
Read Explanation:
The value of x is 2152 (or 1532).
1: Isolate x
To find the value of x, subtract the mixed fraction on the left side from the right side:
x=853−6157
2: Separate whole numbers and fractions
You can subtract the whole numbers and the fractions separately:
Whole numbers:
8−6=2Fractions:
53−157
3: Find a common denominator
The Lowest Common Multiple (LCM) of 5 and 15 is 15. Convert 53 to have a denominator of 15:
5×33×3=159
Now, subtract the fractions:
159−157=152
4: Combine the results
Put the whole number and fraction back together:
x=2152
To express it as an improper fraction:
x=15(2×15)+2=1532=2152
