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For a rectangular cross-section beam subjected to maximum shear force F, the shear stress at the top edge is

Azero

Bmaximum

Cdirectly proportional to F

Dinversely proportional to F

Answer:

A. zero

Read Explanation:

The shear stress distribution for a rectangular cross-section beam subjected to maximum shear force F, τ=FAy^bI=F2I(d24y2)\tau= \frac {FA \hat y}{ bI} = \frac {F}{2I} (\frac {d ^ 2}{4}- y ^ 2) . Shear stress is zero at the top and bottom fibre (y = d / 2) and maximum at neutral axis ( y = 0).

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