Question

For a shaft transmitting power 'P' at rpm N, the diameter of shaft would be proportional to

• A. $$(\frac PN)^{1/3}$$
• B. $$(\frac PN)^{1/2}$$
• C. $$(\frac PN)^{2/3}$$
• D. $$(\frac PN)^{3}$$

Answer 1

Answer:

$$(\frac PN)^{1/3}$$

The diameter of a shaft transmitting power P at rpm N is proportional to$(\frac P N) ^ {1/3}$ This is derived from the torsion equation using torque, shear stress, polar moment of inertia, and shaft radius. Thus, as power and rpm increase, the diameter of the shaft must also increase to handle the increased stress.